Fieldwork: quadrats, transects and population estimates explained
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Ecologists want to know how many of a plant or animal live in a habitat, and why they are found where they are. It would take far too long to count every daisy on a school field, so they take a sample and use it to estimate.
This matters because conservation, farming and planning all need information about populations. It is also one of the required practicals, and the calculations are marks you can pick up with a little practice.
By the end you will be able to describe how to sample with a quadrat and with a transect, calculate a mean and a population estimate, and interpret the results.
Why we take a sample
It is not practical to count every organism in a large area. Instead, we sample a small part of the habitat and use it to estimate the whole. For this to work, the sample has to be representative, which means it has to give a fair picture of the whole area.
Random sampling avoids bias. If you choose where to put the quadrats yourself, you might pick the places with more plants. Random placement gives every part of the area an equal chance of being sampled.
A larger sample is better because it reduces the effect of chance. Ten quadrats give a more reliable mean than two. The data is also more reliable if the work is repeated.
Using a quadrat
A quadrat is a square frame, often 1 m by 1 m (area 1 m²) or 0.5 m by 0.5 m (area 0.25 m²). Lay two long tape measures at right angles along the sides of the area to make a grid. Use a calculator or random number table to choose two numbers for a position, then place the quadrat there.
Count the number of the organism you are studying inside the quadrat. Record the number. Move on to the next random position. Repeat for a good number of quadrats, such as 10 or 20.
When plants are too close together to count individually, such as grass or moss, estimate the percentage cover instead. This is the percentage of the quadrat covered by the plant. Always use the same quadrat size and the same rule for plants on the edge of the frame.
A square quadrat frame laid on the ground with several plants inside, divided into a grid of smaller squares that can be used to estimate percentage cover.
Calculating a mean and estimating a population
Find the mean number per quadrat: add up all the counts and divide by the number of quadrats. For counts of 4, 6, 8, 5 and 7, the total is 30 and the mean is 30 ÷ 5 = 6.
Then work out the number per square metre. If each quadrat is 0.25 m², the mean per m² is 6 ÷ 0.25 = 24. To estimate the whole population multiply by the total area. For a field of 400 m², the estimate is 24 × 400 = 9600.
In one line: population estimate = (mean number per quadrat ÷ area of one quadrat) × total area. The answer is only an estimate because it comes from a sample.
Transects
Sometimes you want to find out how the numbers of organisms change across a habitat, for example from the edge of a path into a wood, or up a seashore. Lay a tape measure across the area. This is a transect.
In a line transect you record the organisms that touch the line at set intervals. In a belt transect you place a quadrat at set intervals along the line (for example every 2 m), count the organisms in each, and so sample a belt of known width. A belt transect gives more information than a line transect.
Record at the same distances each time, use the same size quadrat, and repeat the transect if you can. The data can be plotted as a graph of distance against number or percentage cover.
Linking results to abiotic factors
To explain a pattern, measure an abiotic factor at each point on the transect. Use a light meter for light intensity, a soil moisture meter for moisture, a thermometer for temperature and a pH probe for the soil pH.
Look for a pattern. If the number of daisies falls as you move into the shade of a tree, and the light intensity also falls, the results suggest that light affects where daisies grow. A correlation like this does not prove that light is the cause, so other factors such as soil moisture need to be checked.
Judging the investigation
To judge the quality of the investigation, ask whether the sample was large enough, whether the quadrats were placed at random, and whether the measurements were made at the same time of day and in similar weather.
Say how it could be improved: use more quadrats, repeat the transect on a different day, or measure more abiotic factors.
Take care of yourself outdoors: check for hazards such as uneven ground and stinging plants, wear suitable clothing, do not touch or taste plants, and wash your hands afterwards.
Recap
A sample is used to estimate a population. Random placement avoids bias and a larger sample reduces the effect of chance.
Population estimate = (mean per quadrat ÷ quadrat area) × total area. A transect shows how organisms change across a habitat.
Measure abiotic factors along the transect to explain the pattern, but remember that a correlation does not prove cause.
Key points
Sample randomly to avoid bias. A larger sample is more reliable.
Mean per quadrat → per m² (÷ quadrat area) → whole area (× total area).
A transect shows change across a habitat. Measure abiotic factors along it.
Percentage cover is used when plants are too dense to count.
Worked examples
Example 1
Five 1 m² quadrats contain 8, 11, 9, 12 and 10 daisies. Calculate the mean number of daisies per quadrat.
Add the counts: 8 + 11 + 9 + 12 + 10 = 50.
Divide by the number of quadrats: 50 ÷ 5.
The mean is 10 daisies per quadrat.
Answer: 10 daisies per quadrat
Common slips
Slip: 50 daisies That is the total. Divide by the number of quadrats to get the mean.
Slip: 50 ÷ 4 = 12.5 There are 5 quadrats, so divide by 5.
Slip: The middle value is 10, so the mean is 10. The answer is right but the method is the median. For the mean add them and divide by 5.
Example 2
A field has an area of 600 m². The mean number of dandelions in 0.5 m² quadrats is 3. Estimate the number of dandelions in the field.
Number per m² = 3 ÷ 0.5 = 6.
Population estimate = number per m² × total area.
6 × 600 = 3600 dandelions.
Answer: 3600 dandelions
Common slips
Slip: 3 × 600 = 1800 The quadrat was 0.5 m², not 1 m². Convert to the number per m² first.
Slip: 3 × 0.5 × 600 = 900 You multiplied by the quadrat area. Divide by it.
Slip: 3 ÷ 600 = 0.005 To scale up, multiply by the area.
Example 3
A belt transect from a hedge into a field shows the number of buttercups per quadrat at 0 m, 2 m, 4 m, 6 m and 8 m: 0, 2, 5, 9, 11. The light intensity is 20, 40, 70, 90 and 100 units. Describe the pattern and suggest an explanation. Why is the evidence not proof?
The number of buttercups increases as you move away from the hedge: 0 up to 11.
The light intensity also increases away from the hedge, from 20 to 100 units.
This suggests that buttercups grow better where there is more light, as the hedge shades them.
It is only a correlation: other factors such as soil moisture or pH could also change along the transect.
Answer: More buttercups where light is higher, away from the hedge. This is a correlation, so it does not prove that light is the cause
Common slips
Slip: The number falls away from the hedge. The counts rise from 0 to 11 as you move away from the hedge.
Slip: The light causes the buttercups to appear. A correlation does not prove cause. Other factors could be responsible.
Slip: More buttercups means less light. More buttercups go with more light in this data.
Slip: The results prove that light intensity controls growth. Data from one transect shows a link but does not prove the cause.
Questions and answers
Fieldwork: quadrats, transects and population estimates practice questions for GCSE Combined Science Biology. Try each one, then open the answer. Easy questions come first.
Question 1 Easy
What name is given to a square frame used to sample an area?
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Answer: quadrat
It is used to sample organisms.
It is a quadrat.
Question 2 Easy
Should quadrats be placed at random or where you can see lots of plants?
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Answer: at random
Random placement avoids bias.
Place them at random.
Question 3 Easy
What is the name for a line used to see how organisms change across a habitat?
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Answer: transect
A tape laid across the habitat.
It is a transect.
Question 4 Easy
Name one abiotic factor you could measure along a transect.
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Answer: light intensity
Abiotic factors are non-living.
Light intensity is one.
Question 5 Easy
What is the name for all the organisms of one species living in an area?
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Answer: population
One species in one area.
It is a population.
Question 6 Medium
Five quadrats contain 8, 11, 9, 12 and 10 daisies. Calculate the mean number per quadrat.
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Answer: 10
Total = 8 + 11 + 9 + 12 + 10 = 50.
50 ÷ 5 = 10.
Question 7 Medium
The mean number of plants in 0.25 m² quadrats is 6. How many plants are there per m²?
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Answer: 24
A quadrat is a quarter of a m².
6 ÷ 0.25 = 24.
Question 8 Medium
There are 24 plants per m² in a field of 400 m². Estimate the total number of plants.
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Answer: 9600
Multiply the number per m² by the area.
24 × 400 = 9600.
Exam-style questions
Longer questions in the style of a written paper, with the marking points. These are Yumio practice questions.
Exam-style question 16 marks
Describe how you would estimate the number of daisies on a school field using quadrats. [6 marks]
Show answer and marking points
Answer: Mark out a grid on the field with two tape measures at right angles. Use random numbers as coordinates to place a quadrat. Count the number of daisies inside the quadrat. Repeat for at least ten quadrats to give a large sample. Calculate the mean number of daisies per quadrat. Divide by the area of one quadrat, then multiply by the total area of the field to estimate the population.
make a grid with tape measures (1)
use random numbers or coordinates to place the quadrats (1)
count the daisies in each quadrat (1)
repeat for a large number of quadrats (1)
calculate the mean per quadrat (1)
scale up to the area of the field (1)
Exam-style question 24 marks
(a) A field has an area of 500 m². The mean number of plants in 0.25 m² quadrats is 4. Calculate the estimated number of plants in the field. [3 marks] (b) Give one reason why this is only an estimate. [1 mark]
Show answer and marking points
Answer: (a) 8000 (b) it is based on a sample, not on counting every plant
(a) 4 ÷ 0.25 = 16 (1)
(a) 16 × 500 (1)
(a) 8000 (1)
(b) based on a sample or not every plant was counted (1)
Common mistakes
Placing the quadrats where there are plenty of plants
Place them at random, using random numbers, to avoid bias.
Using too few quadrats
A larger sample is more reliable because it reduces the effect of chance.
Forgetting to convert the quadrat area
Divide the mean by the area of one quadrat to get the number per m².
Saying a correlation proves the cause
Other factors could cause the pattern, so you can only suggest an explanation.
Confusing a line transect with a belt transect
A line transect records what touches the line. A belt transect uses quadrats along the line.
Questions students ask
Is Fieldwork: quadrats, transects and population estimates on the Foundation or Higher tier?
Fieldwork: quadrats, transects and population estimates is on both Foundation and Higher papers for GCSE Combined Science Biology, aimed at around grade 5.
What is a common mistake on Fieldwork: quadrats, transects and population estimates?
Placing the quadrats where there are plenty of plants. Place them at random, using random numbers, to avoid bias.
Where are the answers to the Fieldwork: quadrats, transects and population estimates questions?
Open Show answer under each question on this page. The questions are Yumio practice questions, not past exam questions.