Why mass is conserved in a reaction, how to calculate relative formula mass, and how to explain apparent changes in mass.
Objectives
Explain that the total mass of reactants equals the total mass of products in a closed system.
Calculate the relative formula mass (Mr) of a compound from relative atomic masses.
Use the idea of conservation of mass to find the mass of a missing reactant or product.
Explain why the mass of a solid can appear to increase or decrease when a gas takes part in a reaction.
Specification references this topic covers: AQA 5.3.1; Edexcel C1.26, C1.47.
Relative formula mass and conservation of mass explained
Start here
When you burn a candle, it seems to disappear. When you bake a cake, the mixture seems to change completely. Chemistry has a simple rule that explains what really happens to the mass.
This matters because it lets you predict masses before you do an experiment. Chemists use it to work out how much of a substance they will make. It is also the start of all the calculations in this topic.
By the end you will be able to find a missing mass. You will calculate the relative formula mass of a compound. You will also explain why a mass can seem to go up or down.
Conservation of mass
No atoms are made or destroyed in a chemical reaction. They are rearranged into new substances. So the total mass of the reactants equals the total mass of the products. This is the law of conservation of mass. Think of a Lego house rebuilt into a car. The bricks are the same, so the mass is the same.
If you know every mass but one, subtract. Say 12 g of magnesium reacts with oxygen to make 20 g of magnesium oxide. The oxygen is 20 − 12 = 8 g.
Relative atomic mass and relative formula mass
The relative atomic mass, Ar, of an element is shown on the periodic table. It compares the mass of an atom with other atoms. Use these values. H = 1, C = 12, N = 14, O = 16, Na = 23. Mg = 24, S = 32, Cl = 35.5, Ca = 40.
The relative formula mass, Mr, of a compound is the sum of the Ar values in its formula. Add one for every atom. Mr has no units. For water, H₂O, Mr = 2 × 1 + 16 = 18.
Calculating Mr
Write out each element, multiply its Ar by the number of atoms, then add. For carbon dioxide, CO₂: 12 + 2 × 16 = 44. For sodium hydroxide, NaOH: 23 + 16 + 1 = 40.
With brackets, multiply everything inside the bracket by the number outside. For calcium hydroxide, Ca(OH)₂: 40 + 2 × (16 + 1) = 40 + 34 = 74.
Think of a shopping basket. Each item has a price, and you multiply by how many you bought, then add up.
Bars showing relative formula masses: water 18, carbon dioxide 44, sodium hydroxide 40 and calcium hydroxide 74.
Mr and balanced equations
The masses in a balanced equation also add up. Take 2Mg + O₂ → 2MgO. The left side is 2 × 24 + 32 = 80. The right side is 2 × (24 + 16) = 80.
Multiply the Mr by the big number in front of the formula, then add. If both sides match, the equation is balanced and your Mr values are probably right. If they do not match, check your sums again.
Why mass can seem to change
Sometimes the mass appears to change. This happens when a gas is a reactant or a product, and the container is open. Gases are very light and you cannot see them. The gas is not weighed, so it seems to appear or disappear.
If a gas is a reactant, the solid seems to gain mass. If a gas is a product, the mass seems to fall because the gas escapes. It is like a fizzy drink going flat in an open glass. If the container is sealed, the total mass does not change.
Mass going up and mass going down
When magnesium burns, 2Mg + O₂ → 2MgO. The white powder is heavier than the magnesium. The extra mass is the oxygen that joined it. If 2.4 g of magnesium makes 4.0 g of magnesium oxide, the oxygen is 4.0 − 2.4 = 1.6 g.
When a metal carbonate is heated in an open tube, carbon dioxide escapes. The solid left is lighter. Say 5.0 g of a metal carbonate leaves 3.1 g of solid. The gas lost is 5.0 − 3.1 = 1.9 g.
Recap
Mass is conserved because atoms are rearranged, not made or destroyed.
Mr is the sum of the Ar values for every atom in the formula. Multiply by any number outside brackets.
In an open container, a gas joining makes the mass seem to rise. A gas leaving makes it seem to fall.
To find a missing mass, subtract the masses you know.
Key points
The total mass of reactants equals the total mass of products. Atoms are rearranged, not created or destroyed.
Mr is the sum of the Ar values for all the atoms in the formula.
Use big numbers from the balanced equation to multiply the Mr values.
An apparent mass change in an open container is caused by a gas joining or leaving.
Worked examples
Example 1
Calculate the relative formula mass of carbon dioxide, CO₂. Ar of C = 12 and Ar of O = 16.
One carbon atom and two oxygen atoms.
Mr = 12 + 2 × 16.
Mr = 44.
Answer: 44
Common slips
Slip: Mr = 12 + 16. The formula has two oxygen atoms, so multiply 16 by 2.
Slip: Mr = 12 × 2 × 16 = 384. You add the Ar values. You multiply only by the number of atoms.
Slip: Mr = 28. That is 12 + 16, which leaves out one O.
Example 2
Calculate the relative formula mass of ammonium sulfate, (NH₄)₂SO₄. Ar of N = 14, H = 1, S = 32 and O = 16.
Inside the bracket: N + 4 × H = 14 + 4 = 18. There are two of them: 2 × 18 = 36.
Sulfate: 32 + 4 × 16 = 96.
Mr = 36 + 96 = 132.
Answer: 132
Common slips
Slip: (NH₄)₂ = 14 + 4 × 2 = 22. The 2 outside the bracket multiplies both N and H.
Slip: SO₄ = 32 + 16 = 48. There are four oxygen atoms, so 4 × 16 = 64.
Slip: Mr = 36 + 32 + 16 = 84. Sulfate is S and O₄, so 32 + 64 = 96.
Example 3
A student heats 4.0 g of magnesium ribbon in an open crucible. The magnesium reacts completely. The mass of the white product is 6.6 g. Calculate the mass of oxygen that reacted, and explain why the measured mass of product is higher than 4.0 g.
Mass of oxygen = mass of product − mass of magnesium.
6.6 − 4.0 = 2.6 g.
The product contains magnesium and the oxygen from the air that joined it, so it is heavier.
Answer: 2.6 g, because the oxygen from the air joined the magnesium
Common slips
Slip: 6.6 + 4.0 = 10.6 g. The product contains both masses. Subtract to find the oxygen.
Slip: Oxygen = 4.0 − 6.6 = −2.6 g. Mass cannot be negative. Subtract the smaller from the larger.
Slip: Mass is created in the reaction. Mass is not created. The mass added is oxygen from the air.
Questions and answers
Relative formula mass and conservation of mass practice questions for GCSE Combined Science Chemistry. Try each one, then open the answer. Easy questions come first.
Question 1 Easy
What is the relative formula mass of water, H₂O? Ar of H = 1 and Ar of O = 16.
Show answer
Answer: 18
Two hydrogen atoms: 2 × 1 = 2.
2 + 16 = 18.
Question 2 Easy
2.0 g of hydrogen reacts with 16 g of oxygen. What is the total mass of water formed?
Show answer
Answer: 18 g
Mass is conserved.
2.0 + 16 = 18 g.
Question 3 Easy
What is the relative formula mass of sodium hydroxide, NaOH? Ar of Na = 23, O = 16 and H = 1.
Show answer
Answer: 40
Add 23 + 16 + 1.
Mr = 40.
Question 4 Easy
In a closed system, 5 g of reactants make products. What is the total mass of the products in grams?
Show answer
Answer: 5
Mass is conserved.
The products have a mass of 5 g.
Question 5 Easy
What is the relative formula mass of carbon monoxide, CO? Ar of C = 12 and Ar of O = 16.
Show answer
Answer: 28
Add the Ar values of one carbon and one oxygen.
12 + 16 = 28.
Question 6 Easy
3 g of carbon reacts completely with 8 g of oxygen to make carbon dioxide. What is the mass of carbon dioxide in grams?
Show answer
Answer: 11 g
Mass is conserved.
3 + 8 = 11 g.
Question 7 Medium
Calculate the relative formula mass of calcium hydroxide, Ca(OH)₂. Ar of Ca = 40, O = 16 and H = 1.
Show answer
Answer: 74
O and H in the bracket: 16 + 1 = 17.
40 + 2 × 17 = 74.
Question 8 Medium
Calculate the relative formula mass of sulfuric acid, H₂SO₄. Ar of H = 1, S = 32 and O = 16.
Show answer
Answer: 98
2 × 1 = 2, then 32, then 4 × 16 = 64.
2 + 32 + 64 = 98.
Exam-style questions
Longer questions in the style of a written paper, with the marking points. These are Yumio practice questions.
Exam-style question 14 marks
Calcium carbonate decomposes when heated: CaCO₃ → CaO + CO₂.
(a) Calculate the relative formula mass of calcium carbonate. Ar of Ca = 40, C = 12 and O = 16. [2 marks]
(b) A student heats 10.0 g of calcium carbonate in an open tube. Explain why the mass of solid left is less than 10.0 g. [2 marks]
Show answer and marking points
Answer: (a) 100 (b) Carbon dioxide gas is made and escapes from the open tube, so it is not included in the mass of the solid left.
(a) 40 + 12 + 3 × 16 (1)
(a) 100 (1)
(b) carbon dioxide is made, which is a gas (1)
(b) it escapes from the open tube (1)
Exam-style question 25 marks
(a) Calculate the relative formula mass of magnesium nitrate, Mg(NO₃)₂. Ar of Mg = 24, N = 14 and O = 16. [2 marks]
(b) 4.8 g of magnesium reacts completely with oxygen to make 8.0 g of magnesium oxide. Calculate the mass of oxygen that reacted. [1 mark]
(c) Explain how this shows that mass is conserved. [2 marks]
Show answer and marking points
Answer: (a) 148 (b) 3.2 g (c) The mass of the magnesium plus the mass of the oxygen equals the mass of the magnesium oxide, so no atoms are lost or made.
(a) 2 × (14 + 48) = 124 or 24 + 124 (1)
(a) 148 (1)
(b) 3.2 g (1)
(c) masses of reactants equal the mass of product (1)
(c) atoms are not made or destroyed, only rearranged (1)
Common mistakes
Not multiplying by the number of atoms in a formula
In H₂O the 2 means two hydrogen atoms, so use 2 × 1.
Ignoring the bracket multiplier
In Ca(OH)₂ the 2 multiplies both O and H.
Saying mass is lost when a gas escapes from an open container
Mass is still conserved. The gas has left the container so it is not weighed.
Giving a unit for Mr
Relative formula mass has no unit.
Questions students ask
Is Relative formula mass and conservation of mass on the Foundation or Higher tier?
Relative formula mass and conservation of mass is on both Foundation and Higher papers for GCSE Combined Science Chemistry, aimed at around grade 4.
What is a common mistake on Relative formula mass and conservation of mass?
Not multiplying by the number of atoms in a formula. In H₂O the 2 means two hydrogen atoms, so use 2 × 1.
Where are the answers to the Relative formula mass and conservation of mass questions?
Open Show answer under each question on this page. The questions are Yumio practice questions, not past exam questions.