force applied to a spring = spring constant × extension
F=ke
F force (N)
k spring constant (N/m)
e extension (m)
elastic potential energy = ½ × spring constant × extension²
Ee=21ke2
Eₑ elastic potential energy (J)
k spring constant (N/m)
e extension (m)
Forces and elasticity explained
Start here
Think about the spring inside a pen. You press the button and the spring squashes. Let go and it springs back. Now think about a trampoline. You push the springs down, and they push you back up into the air.
Springs are everywhere. They are in mattresses, car suspension, bathroom scales and the clips on clothes pegs. A spring is useful because it stores energy when it is stretched or squashed, and then gives it back.
Now compare a spring with a lump of plasticine. Squash the plasticine and it stays squashed. Squash the spring and it springs back to its old shape. That difference is the first big idea in this lesson.
The second big idea is a pattern. Hang one weight on a spring and it stretches a little. Hang two weights and it stretches twice as much. One short equation captures that pattern, and it is the one you will use most.
By the end you will be able to do three things. You will tell elastic from inelastic and work out an extension. You will use force = spring constant × extension and read a force-extension graph. You will explain what the limit of proportionality means.
One more idea comes at the end. It is the energy stored in a stretched spring, and it uses a square, so take care with it.
Stretching and squashing
To stretch, squash or bend something you need more than one force. Hold a spring by one end and it just hangs there, but fix one end to a stand and pull the other, and the stand pushes back. Those two forces stretch the spring, and squashing needs two forces that push towards each other.
The extension is how much longer a spring gets: extension = new length − natural length. The natural length is the length with no force on it. A spring that is 10 cm long and stretches to 14 cm has an extension of 4 cm.
Changing the shape of an object is called distorting it. If the object goes back to its original shape when the force is removed, the distortion is elastic. A spring and an elastic band are elastic objects.
If the object stays changed when the force is removed, the distortion is inelastic. Plasticine is inelastic. So is a paper clip that you bend too far, because it stays bent.
Be careful with the word extension. It is not the whole length of the stretched spring. It is only the extra length, and in your sums you will almost always use the extension.
A spring hanging from a stand with a 200 gram load. The extension is marked as 4 centimetres, the extra length. The weight acts down and the spring force acts up.
Measuring extension
You can test a spring in class. Clamp the spring to a stand next to a ruler and measure its natural length first. Always wear safety glasses in case a spring snaps, and read the ruler at eye level.
Hang a 100 g mass on the spring. A 100 g mass is 0.1 kg, so its weight is 0.1 × 10 = 1 N. Take g = 10 N/kg. Read the new length from the ruler and write it in a table.
Add another 100 g mass and repeat. Each time, work out the extension by taking away the natural length. Each mass adds 1 N to the force.
The table shows a spring with a natural length of 10 cm. Each extra newton makes it 2 cm longer. So 1 N gives 2 cm, 2 N gives 4 cm and 3 N gives 6 cm.
Watch your units. The spring constant is measured in N/m, so convert the extension from centimetres to metres by dividing by 100, and an extension of 4 cm is 0.04 m. Forgetting this is one of the most common ways to lose marks.
The spring constant
Look at the table again. Double the force and the extension doubles, and treble the force and the extension trebles. We say the force and the extension are directly proportional.
This pattern is called Hooke's law: force = spring constant × extension, or F = k × e in symbols. The force is in N, the extension is in m and the spring constant k is in N/m. Use it for any spring that is stretched by a force.
The spring constant tells you how stiff the spring is. A stiff spring has a large k, so it takes a big force to stretch it by 1 m. A soft spring has a small k.
To find the force, multiply: F = k × e. A spring with k = 80 N/m stretched by 0.1 m needs 80 × 0.1 = 8 N. To find the extension, rearrange to e = F ÷ k. To find the spring constant, use k = F ÷ e.
Before you start, check that the extension is in metres, and if it is in cm, change it first. Then write the equation, substitute the numbers and give the unit. The unit of k is newtons per metre, N/m, which is just force ÷ extension.
A formula triangle with F on top and k and e underneath. Force equals spring constant times extension.
Force-extension graphs
A graph makes the pattern easy to see. Put the extension along the bottom and the force up the side, then plot each pair of readings from your table as a point. Use a ruler to draw the best straight line through the points.
For a spring that obeys Hooke's law, the points make a straight line through the origin, which is the point (0, 0). This shows that force is directly proportional to extension. No force means no extension, and double the force means double the extension.
The steepness of the line is its gradient. gradient = change in force ÷ change in extension. On a force-extension graph, the gradient is the spring constant k.
In this graph the line rises from 0 N to 8 N while the extension goes from 0 to 0.2 m. The gradient is 8 ÷ 0.2 = 40 N/m. So this spring has a spring constant of 40 N/m.
A steeper line means a stiffer spring and a shallower line means a softer one, so two springs on the same axes can be compared at a glance. Check which way round the axes are. If they are swapped, the gradient becomes extension ÷ force, which is not k.
A force-extension graph. A straight line through the origin rises to 8 newtons at an extension of 0.2 metres, so the gradient is 40 newtons per metre.
The limit of proportionality
Springs do not follow Hooke's law forever. If you keep adding weights, the spring eventually stops behaving in the neat way, and the point where this happens is called the limit of proportionality. Think of it as the edge of the rule, beyond which the pattern no longer holds.
Up to the limit, the force-extension line is straight. Beyond it the line bends and gets flatter. The extension grows faster than the force, so the extension is no longer proportional to the force.
Past the limit, F = k × e no longer works. Do not use it for those readings. It only works for the straight part of the graph.
Stretch a spring too far and it may be damaged. It may not go back to its original length when the weights are removed. It has then been permanently stretched, which is inelastic distortion.
In an exam, spot the limit by looking for where the straight line starts to curve. Say that the force is no longer proportional to the extension. Do not say the spring breaks, as that is a different point.
A straight line through the origin on a force-extension graph shows a linear relationship: the force is directly proportional to the extension. Beyond the limit of proportionality the line curves, so the relationship is non-linear and doubling the force no longer doubles the extension. Only the straight part obeys F = k × e.
A force-extension graph. The line is straight up to an extension of 0.2 metres, then curves and gets flatter, showing the spring is past its limit of proportionality.
Energy stored in a spring
When you stretch a spring, you do work on it, and the work is transferred to the elastic potential store of the spring. When you let go, the spring gives that energy back, which is how a pull-back toy car gets its movement.
A catapult is a good picture. Pull back the elastic and you store energy. Let go and the energy is transferred to the kinetic store of the stone.
For a spring that obeys Hooke's law, energy stored = 0.5 × spring constant × extension². In symbols, Ee = ½ × k × e². The energy is in J, the spring constant is in N/m and the extension is in m.
Notice that the extension is squared. Square it first, then multiply by ½ and by k. A spring with k = 100 N/m stretched by 0.1 m stores 0.5 × 100 × 0.1² = 0.5 × 100 × 0.01 = 0.5 J.
Because of the square, doubling the extension makes the energy four times bigger. In the bars, k = 50 N/m. An extension of 0.1 m stores 0.25 J, 0.2 m stores 1 J and 0.4 m stores 4 J. A common slip is to forget to square the extension.
Bars showing the energy in joules stored in a spring with a spring constant of 50 newtons per metre at extensions of 0.1, 0.2 and 0.4 metres. The energy is 0.25, 1 and 4, rising four times each time the extension doubles.
Recap
A spring needs two forces to stretch it. The extension is the new length minus the natural length. Elastic distortion goes back to the original shape, and inelastic distortion does not. A paper clip bent too far is a good example of the second kind.
force = spring constant × extension, F = k × e. The force is in N, the extension is in m and k is in N/m. A stiff spring has a large k, and a soft spring has a small one.
On a force-extension graph, a straight line through the origin shows direct proportion, and its gradient is k. Beyond the limit of proportionality the line curves, and F = k × e no longer works.
Energy stored = ½ × k × e². Doubling the extension stores four times as much energy.
How this is asked in an exam: a spring calculation is usually two marks, one for the substitution and one for the answer with its unit. Convert centimetres to metres first. Graph questions ask you to find k from the gradient or to say what a curve shows. When you describe a curve, say that force is no longer proportional to extension.
A quick self-test before you move on. Cover the page and say the equation, the unit of the spring constant and what the limit of proportionality means. If you can also change 5 cm into metres, you are ready for the practice questions.
Key points
extension = new length − natural length. Two forces are needed to stretch a spring.
force = spring constant × extension, F = k × e, with e in metres and k in N/m.
A straight line through the origin on a force-extension graph shows direct proportion, and its gradient is k.
Beyond the limit of proportionality the line curves and F = k × e no longer works.
Elastic distortion goes back to the original shape. Inelastic distortion does not.
Energy stored = ½ × k × e².
Worked examples
Example 1
A spring has a spring constant of 20 N/m. Calculate the force needed to stretch it by 0.5 m.
Write the equation: force = spring constant × extension.
Substitute the numbers: force = 20 × 0.5.
Work out the answer and add the unit: 10 N.
Answer: 10 N
Common slips
Slip: force = spring constant ÷ extension Hooke's law multiplies the spring constant by the extension.
Slip: 20 + 0.5 = 20.5 Multiply, do not add.
Slip: 40 N 20 × 0.5 is 10. The 40 came from dividing 20 by 0.5.
Example 2
A force of 12 N stretches a spring that has a spring constant of 40 N/m. Calculate the extension.
Rearrange F = k × e to e = F ÷ k.
Substitute the numbers: e = 12 ÷ 40.
Work out the answer and add the unit: 0.3 m.
Answer: 0.3 m
Common slips
Slip: extension = force × spring constant To find the extension, divide the force by the spring constant.
Slip: 40 ÷ 12 = 3.3 The force goes on top: 12 ÷ 40.
Slip: 480 m That multiplies 12 by 40. Divide instead.
Example 3
A force of 2 N stretches a spring by 4 cm. Calculate the spring constant in N/m.
Convert the extension to metres: 4 cm ÷ 100 = 0.04 m.
Rearrange F = k × e to k = F ÷ e, then substitute: k = 2 ÷ 0.04.
Work out the answer with its unit: 50 N/m.
Answer: 50 N/m
Common slips
Slip: 4 cm × 100 = 400 m To change centimetres to metres, divide by 100.
Slip: k = F × e = 2 × 0.04 To find the spring constant, divide the force by the extension.
Slip: k = 2 ÷ 4 = 0.5 N/m That used 4 cm without converting it. The extension must be in metres.
Questions and answers
Forces and elasticity practice questions for GCSE Combined Science Physics. Try each one, then open the answer. Easy questions come first.
Question 1 Easy
A spring has a spring constant of 30 N/m. Work out the force to stretch it by 0.2 m.
Show answer
Answer: 6 N
force = spring constant × extension
30 × 0.2 = 6 N
Question 2 Easy
A spring has a spring constant of 100 N/m. Work out the force to stretch it by 0.05 m.
Show answer
Answer: 5 N
force = spring constant × extension
100 × 0.05 = 5 N
Question 3 Easy
Name the unit of the spring constant.
Show answer
Answer: newtons per metre
It links force and extension.
The unit is newtons per metre.
Question 4 Easy
What word describes a spring that returns to its original length when the force is removed?
Show answer
Answer: elastic
It goes back to shape.
The distortion is elastic.
Question 5 Medium
A force of 8 N stretches a spring that has a spring constant of 40 N/m. Work out the extension.
Show answer
Answer: 0.2 m
extension = force ÷ spring constant
8 ÷ 40 = 0.2 m
Question 6 Medium
A force of 15 N stretches a spring by 0.3 m. Work out the spring constant.
Show answer
Answer: 50 N/m
spring constant = force ÷ extension
15 ÷ 0.3 = 50 N/m
Question 7 Medium
State what is meant by the limit of proportionality.
Show answer
Answer: The point beyond which force is no longer proportional to extension.
Up to a point force is proportional to extension.
Beyond it, they are no longer proportional.
Question 8 Medium
State what the gradient of the straight part of a force-extension graph represents.
Show answer
Answer: the spring constant
gradient = force ÷ extension
This is the spring constant.
Exam-style questions
Longer questions in the style of a written paper, with the marking points. These are Yumio practice questions.
Exam-style question 14 marks
A spring has a spring constant of 25 N/m. A student hangs a weight on it and the spring stretches by 0.4 m.
(a) Work out the force exerted by the weight. [2 marks]
(b) Work out the energy stored in the spring. [2 marks]
Show answer and marking points
Answer: (a) 10 N (b) 2 J
(a) force = spring constant × extension (1)
(a) 10 N (1)
(b) 0.5 × 25 × 0.4² (1)
(b) 2 J (1)
Exam-style question 24 marks
A student measures the force needed to stretch a spring and plots a force-extension graph.
(a) State what a straight line through the origin shows. [1 mark]
(b) State what the student can work out from the gradient of the straight part. [1 mark]
(c) Describe what happens to the line beyond the limit of proportionality and why this matters. [2 marks]
Show answer and marking points
Answer: (a) Force is proportional to extension. (b) The spring constant. (c) The line curves, so force is no longer proportional to extension and the spring may be permanently stretched.
(a) force is proportional to extension (1)
(b) the spring constant (1)
(c) the line curves (1)
(c) force is no longer proportional, and the spring may not return to its original length (1)
Common mistakes
Using the new length of the spring as the extension
The extension is the increase over the natural length. Take the natural length away from the new length.
Forgetting to square the extension in the energy equation
Ee = ½ × k × e², so the extension is squared before you multiply.
Saying force is proportional to extension for any force
This only holds up to the limit of proportionality. After that the line on the graph curves.
Using centimetres when k is in N/m
Convert the extension to metres first by dividing by 100.
Saying a spring that stays stretched has had elastic distortion
Elastic means it goes back. If it stays changed, the distortion is inelastic.
Questions students ask
Is Forces and elasticity on the Foundation or Higher tier?
Forces and elasticity is on both Foundation and Higher papers for GCSE Combined Science Physics, aimed at around grade 5.
What is a common mistake on Forces and elasticity?
Using the new length of the spring as the extension. The extension is the increase over the natural length. Take the natural length away from the new length.
Where are the answers to the Forces and elasticity questions?
Open Show answer under each question on this page. The questions are Yumio practice questions, not past exam questions.