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Pythagoras – GCSE Maths

Foundation and Higher · Grade 4

Jump to the questions and answers · Download the worksheet (PDF)

Find a missing side in a right-angled triangle by squaring, adding or subtracting, then square-rooting. It is on Foundation and Higher, aimed at grade 4. Free questions with answers are on this page. Worked examples show each line before you try the questions.

In any right-angled triangle the two shorter sides (the ones that touch the right angle) and the hypotenuse (the side opposite the right angle) are locked together by . Square both shorter sides and add to get the hypotenuse squared. If you already know the hypotenuse, square it and subtract the other known square to get the missing shorter side.

The method is the same whether the triangle is drawn as a ladder against a wall, a diagonal of a rectangle, or two points on a coordinate grid. Sketch, mark the right angle, decide whether you are adding squares or subtracting them, then root at the end. Forgetting the square root is the classic way to throw the accuracy mark after doing the hard part.

Exact answers such as are often wanted on the non-calculator paper. On a calculator paper, round only at the last line to 1 decimal place or 3 significant figures as asked, and write the units.

Objectives

Key points

Worked examples

Example 1

A right-angled triangle has shorter sides 3 and 4. How long is the hypotenuse?

3 marks

  1. 3² = 9 and 4² = 16.
  2. 9 + 16 = 25.
  3. √25 = 5.

Answer: 5

Common slips
  • Slip: 5² = 9 and 4² = 16. That changes a number from the question, so it answers a different question.
  • Slip: 9 − 16 = −7. That uses subtraction, but this step needs addition.
  • Slip: √29 = 5. That does not match the working above it.

Example 2

A right-angled triangle has hypotenuse 25 and one shorter side 7. How long is the other shorter side?

3 marks

  1. 25² = 625 and 7² = 49.
  2. 625 − 49 = 576.
  3. √576 = 24.

Answer: 24

Common slips
  • Slip: 27² = 625 and 7² = 49. That changes a number from the question, so it answers a different question.
  • Slip: 625 + 49 = 674. That uses addition, but this step needs subtraction.
  • Slip: √580 = 24. That does not match the working above it.

Example 3

A ladder 29 m long leans against a vertical wall. The foot of the ladder is 20 m from the wall. How high up the wall does the ladder reach?

3 marks

  1. 29² = 841 and 20² = 400.
  2. 841 − 400 = 441.
  3. √441 = 21.

Answer: 21

Common slips
  • Slip: 31² = 841 and 20² = 400. That changes a number from the question, so it answers a different question.
  • Slip: 841 + 400 = 1241. That uses addition, but this step needs subtraction.
  • Slip: √445 = 21. That does not match the working above it.

Questions and answers

GCSE Maths pythagoras questions and answers. Try each one, then open the answer. Easy questions come first.

Question 1 Easy2 marks

A right-angled triangle has shorter sides 6 cm and 8 cm. How long is the hypotenuse?

Show answer

Answer: 10

  1. 6² + 8² = 100.
  2. The square root is 10.
  • M1 — 6² + 8² = 100.
  • A1 — Answer 10

Question 2 Easy2 marks

The hypotenuse is 13 cm and one shorter side is 5 cm. How long is the other shorter side?

Show answer

Answer: 12

  1. 13² − 5² = 144.
  2. The square root is 12.
  • M1 — 13² − 5² = 144.
  • A1 — Answer 12

Question 3 Medium2 marks

A right-angled triangle has shorter sides 3 cm and 3 cm. Give the hypotenuse as a surd.

Show answer

Answer: 3√2

  1. 3² + 3² = 18.
  2. That is 3√2.
  • M1 — 3² + 3² = 18.
  • A1 — Answer 3√2

Question 4 Medium2 marks

An isosceles triangle has equal sides 5 cm and a base of 6 cm. What is the perpendicular height?

Show answer

Answer: 4

  1. Half of the base is 3 cm.
  2. 5² − 3² = 16.
  • M1 — Half of the base is 3 cm.
  • A1 — Answer 4

Question 5 Hard2 marks

The hypotenuse is 17 cm and one shorter side is 8 cm. Give the other side and the area, side first.

Show answer

Answer: 15, 60

  1. The other side is 15 cm.
  2. The area is 1/2 × 8 × 15 = 60.
  • M1 — The other side is 15 cm.
  • A1 — Answer 15, 60

Question 6 Hard2 marks

The distance from (0, 0) to (5, y) is 13. Find the missing positive coordinate y.

Show answer

Answer: 12

  1. 13² − 5² = 144.
  2. The positive coordinate is 12.
  • M1 — 13² − 5² = 144.
  • A1 — Answer 12

Question 7 Exam-style3 marks

The hypotenuse is 25 cm and one shorter side is 7 cm. Give the other side and the area, side first.

Show answer

Answer: 24, 84

  1. The other side is 24 cm.
  2. The area is 1/2 × 7 × 24 = 84.
  • M1 — The other side is 24 cm.
  • M1 — The area is 1/2 × 7 × 24 = 84.
  • A1 — Answer 24, 84

Common mistakes

Most lost marks on this topic are one slip.

  1. Adding the squares when you were finding a shorter side.

    Subtract from the hypotenuse squared.

  2. Square-rooting before you add.

    Add the squares first, then take one square root.

  3. Using Pythagoras on a triangle with no right angle.

    The theorem needs a right angle.

Spot the slip

The hypotenuse is

  1. the longest side, opposite the right angle
  2. either of the shorter sides
  3. the right angle itself
Show the slip

the longest side, opposite the right angle It is the side across from the right angle.

Exam tips

Printable worksheet

The same questions are in a PDF you can print. Answers start on a later page.

Download worksheet (PDF)

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Questions students ask

Is Pythagoras Foundation or Higher?

Pythagoras is on Foundation and Higher, aimed at grade 4.

What is a common slip on Pythagoras?

Adding the squares when you were finding a shorter side. Subtract from the hypotenuse squared.

Where can I get Pythagoras questions and answers?

The questions on this page are free. Open Show answer under each one, or download the worksheet PDF. Start free to practise this topic in the app.

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Last updated 9 November 2026.

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