Work out interior and exterior angles of regular and irregular polygons, and find the number of sides from an angle. It is on Foundation and Higher, aimed at grade 4. Free questions with answers are on this page. Worked examples show each line before you try the questions.
The interior angles of an n-sided polygon sum to (n−2)×180∘. A regular polygon shares that sum equally. Exterior angles of any convex polygon sum to 360∘, and for a regular polygon each exterior angle is 360∘÷n. Interior and exterior at a vertex sit on a straight line, so they add to 180∘.
To find n from an exterior angle, divide 360 by that angle. Do not use the interior-sum formula to find n unless you first find one exterior (or rearrange carefully). A pentagon is 5 sides, a hexagon 6, octagon 8 — write the name if you know it, but n is what the algebra needs.
Interior sum =(n−2)×180∘. Exterior of any convex polygon sums to 360∘, so a regular exterior is 360÷n. Interior of a regular polygon is 180 minus that exterior. Working backwards from an interior angle is the usual 4-mark.
Objectives
One exterior angle is the turn at a corner if you walk around the shape.
At each vertex, the interior and the exterior add to 180°.
A polygon with n sides splits into n − 2 triangles.
Key points
Find the sum of the interior angles of any polygon using (n−2)×180∘.
Work out one interior angle of a regular polygon.
Use the fact that exterior angles always total 360∘.
Find the number of sides of a regular polygon from its exterior or interior angle.
Worked examples
Example 1
A regular polygon has 4 sides. Work out the size of one exterior angle.
2 marks
The exterior angles of any polygon add to 360°.
One exterior angle = 360° ÷ 4.
360° ÷ 4 = 90°.
Answer: 90
Common slips
Slip: The exterior angles of any polygon add to 362°. That changes a number from the question, so it answers a different question.
Slip: One exterior angle = 363° ÷ 4. That changes a number in the working, so the step no longer follows from the one before.
Slip: 364° ÷ 4 = 90°. That does not match the working above it.
Example 2
Work out the sum of the interior angles of a polygon with 16 sides.
2 marks
A polygon with 16 sides splits into 16 − 2 = 14 triangles.
The angles in each triangle add to 180°.
14 × 180° = 2520°.
Answer: 2520
Common slips
Slip: A polygon with 18 sides splits into 16 − 2 = 14 triangles. That changes a number from the question, so it answers a different question.
Slip: The angles in each triangle add to 183°. That changes a number in the working, so the step no longer follows from the one before.
Slip: 18 × 180° = 2520°. That does not match the working above it.
Example 3
A regular polygon has 12 sides. Work out the size of one interior angle.
3 marks
Interior angle sum = (12 − 2) × 180° = 1800°.
One interior angle = 1800° ÷ 12.
1800° ÷ 12 = 150°.
Answer: 150
Common slips
Slip: Interior angle sum = (14 − 2) × 180° = 1800°. That changes a number from the question, so it answers a different question.
Slip: One interior angle = 1803° ÷ 12. That changes a number in the working, so the step no longer follows from the one before.
Slip: 1804° ÷ 12 = 150°. That does not match the working above it.
Questions and answers
GCSE Maths angles in polygons questions and answers. Try each one, then open the answer. Easy questions come first.
Question 1 Easy2 marks
Each exterior angle of a regular polygon is 12°. How many sides does the polygon have?
Show answer
Answer: 30
The exterior angles of any polygon add to 360°.
Number of sides = 360 ÷ 12.
M1 — The exterior angles of any polygon add to 360°.
A1 — Answer 30
Question 2 Easy2 marks
Four of the interior angles of a pentagon are 122°, 119°, 100° and 120°. Work out the size of the remaining angle.
Show answer
Answer: 79
Interior angles of a pentagon add to (5 − 2) × 180° = 540°.
The given angles add to 461°.
M1 — Interior angles of a pentagon add to (5 − 2) × 180° = 540°.
A1 — Answer 79
Question 3 Medium2 marks
A regular polygon has 18 sides. Work out the size of one interior angle.