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Expanding triple brackets – GCSE Maths

Higher · Grade 6 · Non-calculator

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Expand a product of three brackets by multiplying two first, then multiplying the result by the third. It is Higher only, aimed at grade 6. Free questions with answers are on this page. Worked examples show each line before you try the questions.

Three brackets: expand two of them first, then multiply the quadratic by the remaining linear. . A grid of six products for the second step keeps the and terms from collapsing into each other.

Check by putting into the original product and into your cubic — they must match. Collect like terms once at the end, not three times. If a question asks for the coefficient of only, you still need those middle products, but you can ignore the constant if you are careful.

Multiply two brackets first, then the third. A difference of two squares can shrink the first pair. is not — expand then multiply by .

Objectives

Key points

Worked examples

Example 1

Expand (x+1)(x+2)(x+3).

2 marks

  1. Expand the first two brackets: (x+1)(x+2) = x^2 + 3x + 2.
  2. Multiply the quadratic by the third bracket: (x^2 + 3x + 2)(x+3).
  3. Expand and collect terms: x^3 + 3x^2 + 3x^2 + 9x + 2x + 6 = x^3 + 6x^2 + 11x + 6.

Answer: x^3+6x^2+11x+6

Common slips
  • Slip: Multiply only the constants: 1 × 2 × 3 = 6. All terms in each bracket must be multiplied.
  • Slip: Stop at x^2 + 3x + 2. The third bracket (x+3) must still be multiplied.
  • Slip: Leave unsimplified terms. Combine all like terms for the final cubic.

Example 2

Expand (x+1)^3.

2 marks

  1. Write as three repeated linear factors: (x+1)(x+1)(x+1).
  2. Expand the first pair: (x+1)^2 = x^2 + 2x + 1.
  3. Multiply by (x+1): x^3 + 3x^2 + 3x + 1.

Answer: x^3+3x^2+3x+1

Common slips
  • Slip: Cube each term separately: x^3 + 1. Cubing a bracket produces cross terms.
  • Slip: Write x^2 + 2x + 1. That is (x+1)^2. A cube needs one more bracket multiplied in.
  • Slip: Drop the middle terms. Binomial coefficients for a cube are 1, 3, 3, 1.

Example 3

Find the coefficient of x^2 in (x+1)(x+2)(x+3).

3 marks

  1. Recognise that the x^2 term is formed by choosing x from two brackets and a constant from the third.
  2. Sum the three constants: 1 + 2 + 3 = 6.
  3. The coefficient of x^2 is 6.

Answer: 6

Common slips
  • Slip: Multiply all three constants together: 1 × 2 × 3 = 6. Multiplying all constants gives the constant term, not the x^2 coefficient.
  • Slip: Multiply 1 and 2. Each bracket contributes a constant to one of the x^2 terms.
  • Slip: State 6x^2. The question asks for the numerical coefficient.

Questions and answers

GCSE Maths expanding triple brackets questions and answers. Try each one, then open the answer. Easy questions come first.

Question 1 Easy2 marks

Expand (x+1)(x+2)(x+4).

Show answer

Answer: x^3+7x^2+14x+8

  1. First pair: (x+1)(x+2) = x^2 + 3x + 2.
  2. Multiply by (x+4): x^3 + 7x^2 + 14x + 8.
  • M1 — First pair: (x+1)(x+2) = x^2 + 3x + 2.
  • A1 — Multiply by (x+4): x^3 + 7x^2 + 14x + 8.

Question 2 Easy2 marks

Expand (x+2)(x+3)(x+4).

Show answer

Answer: x^3+9x^2+26x+24

  1. First pair: (x+2)(x+3) = x^2 + 5x + 6.
  2. Multiply by (x+4): x^3 + 9x^2 + 26x + 24.
  • M1 — First pair: (x+2)(x+3) = x^2 + 5x + 6.
  • A1 — Multiply by (x+4): x^3 + 9x^2 + 26x + 24.

Question 3 Medium2 marks

Expand (x+2)^3.

Show answer

Answer: x^3+6x^2+12x+8

  1. Expand (x+2)^2 = x^2 + 4x + 4.
  2. Multiply by (x+2): x^3 + 6x^2 + 12x + 8.
  • M1 — Expand (x+2)^2 = x^2 + 4x + 4.
  • A1 — Multiply by (x+2): x^3 + 6x^2 + 12x + 8.

Question 4 Medium2 marks

Expand (x+3)^3.

Show answer

Answer: x^3+9x^2+27x+27

  1. Expand (x+3)^2 = x^2 + 6x + 9.
  2. Multiply by (x+3): x^3 + 9x^2 + 27x + 27.
  • M1 — Expand (x+3)^2 = x^2 + 6x + 9.
  • A1 — Multiply by (x+3): x^3 + 9x^2 + 27x + 27.

Question 5 Hard2 marks

Find the coefficient of x^2 in (x+1)(x+2)(x+4).

Show answer

Answer: 7

  1. Sum the constants from each factor.
  2. 1 + 2 + 4 = 7.
  • M1 — Sum the constants from each factor.
  • A1 — 1 + 2 + 4 = 7.

Question 6 Hard2 marks

Find the coefficient of x^2 in (x+2)(x+3)(x+4).

Show answer

Answer: 9

  1. Sum the constants from each factor.
  2. 2 + 3 + 4 = 9.
  • M1 — Sum the constants from each factor.
  • A1 — 2 + 3 + 4 = 9.

Question 7 Exam-style4 marks

Expand (x+1)(x+3)(x+4).

Show answer

Answer: x^3+8x^2+19x+12

  1. Expand the first pair: (x+1)(x+3) = x^2 + 4x + 3.
  2. Multiply by (x+4): x(x^2 + 4x + 3) + 4(x^2 + 4x + 3).
  3. Expand: x^3 + 4x^2 + 3x + 4x^2 + 16x + 12.
  4. Collect like terms: x^3 + 8x^2 + 19x + 12.
  • M1 — Expand first pair to x^2 + 4x + 3
  • M1 — Multiply quadratic by (x+4)
  • M1 — Collect x^2 terms 8x^2 and x terms 19x
  • A1 — Final expansion x^3 + 8x^2 + 19x + 12

Common mistakes

Most lost marks on this topic are one slip.

  1. Stopping after two of the three brackets

    Multiply by the third bracket

  2. Writing x^3 plus the constant and nothing else for a cube

    Include both middle terms

  3. Multiplying the three numbers when the question asks for the x^2 coefficient

    Add those three numbers

Spot the slip

Ada expands (x+1)(x+2)(x+3) and stops after two brackets. The cubic should be which polynomial?

  1. x^3+6x^2+11x+6
  2. x^2+3x+2
  3. x^3+6x+6
Show the slip

x^3+6x^2+11x+6 The three constants add to the x^2 coefficient: 1+2+3 = 6, and the constant term is 1×2×3.

Exam tips

Printable worksheet

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Questions students ask

Is Expanding triple brackets Foundation or Higher?

Expanding triple brackets is Higher only, aimed at grade 6.

What is a common slip on Expanding triple brackets?

Stopping after two of the three brackets. Multiply by the third bracket.

Where can I get Expanding triple brackets questions and answers?

The questions on this page are free. Open Show answer under each one, or download the worksheet PDF. Start free to practise this topic in the app.

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Last updated 9 November 2026.

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