Question 1 Easy
On the curve y=x^2-9, work out the value of y when x=4.
Show answer
Answer: 7
- Substitute x = 4: 4^2 - 9.
- Calculate: 16 - 9 = 7.
- Method (1): Substitute x = 4: 4^2 - 9.
- Accuracy (1): Calculate: 16 - 9 = 7.
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A second set of drawing quadratic graphs questions for GCSE Maths. They are different from the ones on the topic page, so work through both. Try each question, then open the answer to check your working.
On the curve y=x^2-9, work out the value of y when x=4.
Answer: 7
On the curve y=x^2+3, work out the value of y when x=2.
Answer: 7
Find the roots of the curve y=x^2-25.
Answer: -5 or 5
Find the roots of the curve y=x^2-1.
Answer: -1 or 1
Find the x-values where the curve y=(x-1)(x-4) crosses the x-axis.
Answer: 1 or 4
Find the x-values where the curve y=(x-2)(x-5) crosses the x-axis.
Answer: 2 or 5
A longer question with marks, in the style of a written paper. This is a Yumio practice question, not a past paper question.
Find the x-values where the curve y=(x-3)(x-7) crosses the x-axis.
Answer: 3 or 7
Short one-step questions. Pick an option before you open the answer.
How do you find a y-value on y = x^2 + c for a given x?
Square x then add c Order of operations requires squaring x before adding c.
On y = x^2 - 4, what is the value of y at x = 3?
5 3^2 - 4 = 9 - 4 = 5.
On y = x^2 + 1, what is the value of y at x = 3?
10 3^2 + 1 = 9 + 1 = 10.
What are the roots of the curve y = x^2 - 4?
-2 or 2 x^2 = 4, so x = -2 or 2.
What are the roots of the curve y = x^2 - 9?
-3 or 3 x^2 = 9, so x = -3 or 3.
What is the y-intercept of the curve y = x^2 - 4?
-4 When x = 0, y = -4.
What is the y-intercept of the curve y = x^2 + 3?
3 When x = 0, y = 3.
Where does the curve y = (x-2)(x-3) cross the x-axis?
2 or 3 At y = 0, x - 2 = 0 or x - 3 = 0.
Where does the curve y = (x-1)(x-4) cross the x-axis?
1 or 4 At y = 0, x - 1 = 0 or x - 4 = 0.
What is a root of a quadratic curve?
An x-value where the curve crosses the x-axis Roots are the solutions to y = 0.
At what x-value does the y-intercept always occur?
x = 0 The y-axis is the line x = 0.
Why does y = x^2 - a have two roots when a > 0?
Positive numbers have both a positive and negative square root Square roots can be positive or negative.
On y = x^2 - 9, what is the value when x = 4?
7 4^2 - 9 = 16 - 9 = 7.
What are the roots of y = x^2 - 16?
-4 or 4 x^2 = 16, so x = -4 or 4.
Where does the curve y = (x-2)(x-5) cross the x-axis?
2 or 5 At y = 0, x = 2 or x = 5.
AQA-style and Edexcel-style questions. Yumio is not affiliated with, endorsed by or connected to AQA, Pearson Edexcel or any other exam board.