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Gradient of a line practice questions with answers
Foundation and Higher · Grade 5 · Non-calculator
A second set of gradient of a line questions for GCSE Maths. They are different from the ones on the topic page, so work through both. Try each question, then open the answer to check your working.
More questions
Question 1 Easy
Work out the gradient of the line through (0, 4) and (2, 0).
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Answer: -2
Change in y = 0 - 4 = -4, change in x = 2 - 0 = 2.
Gradient = -4 / 2 = -2.
Method (1): Change in y = 0 - 4 = -4, change in x = 2 - 0 = 2.
Accuracy (1): Gradient = -4 / 2 = -2.
Question 2 Easy
Work out the gradient of the line through (1, 1) and (4, 10).
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Answer: 3
Change in y = 10 - 1 = 9, change in x = 4 - 1 = 3.
Gradient = 9 / 3 = 3.
Method (1): Change in y = 10 - 1 = 9, change in x = 4 - 1 = 3.
Accuracy (1): Gradient = 9 / 3 = 3.
Question 3 Medium
Work out the change in y from (1, 2) to (5, 10).
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Answer: 8
Difference in y-coordinates: 10 - 2.
Result is 8.
Method (1): Difference in y-coordinates: 10 - 2.
Accuracy (1): Result is 8.
Question 4 Medium
Work out the change in y from (2, 6) to (5, 0).
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Answer: -6
Difference in y-coordinates: 0 - 6.
Result is -6.
Method (1): Difference in y-coordinates: 0 - 6.
Accuracy (1): Result is -6.
Question 5 Hard
Work out the change in y from (0, 1) to (4, 9).
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Answer: 8
Difference in y-coordinates: 9 - 1.
Result is 8.
Method (1): Difference in y-coordinates: 9 - 1.
Accuracy (1): Result is 8.
Question 6 Hard
A line has gradient 5 and passes through (0, 2). Work out y when x=1.
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Answer: 7
Equation: y = 5x + 2.
When x = 1: y = 5(1) + 2 = 7.
Method (1): Equation: y = 5x + 2.
Accuracy (1): When x = 1: y = 5(1) + 2 = 7.
Exam-style question
A longer question with marks, in the style of a written paper. This is a Yumio practice question, not a past paper question.
Exam-style question 12 marks
A line has gradient 3 and passes through (0, 5). Work out y when x=4.
Show answer
Answer: 17
Line formula is y = 3x + 5.
Substitute x = 4: y = 3(4) + 5 = 12 + 5 = 17.
Method (1): y = 3x + 5, or 3 × 4 + 5
Accuracy (1): 17
Quick checks
Short one-step questions. Pick an option before you open the answer.
Check 1
What is the formula for the gradient m of a line through (x_A, y_A) and (x_B, y_B)?
m = (y_B - y_A) / (x_B - x_A)
m = (x_B - x_A) / (y_B - y_A)
m = (y_B + y_A) / (x_B + x_A)
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m = (y_B - y_A) / (x_B - x_A) Gradient is vertical rise over horizontal run.
Check 2
What is the gradient of the line through (1, 2) and (5, 10)?
2
0.5
8
Show answer
2 (10 - 2) / (5 - 1) = 8 / 4 = 2.
Check 3
What is the gradient of the line through (0, 4) and (2, 0)?
-2
2
-0.5
Show answer
-2 (0 - 4) / (2 - 0) = -4 / 2 = -2.
Check 4
If y increases as x increases, what is the sign of the gradient?
Positive
Negative
Zero
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Positive Rising from left to right is positive gradient.
Check 5
If y decreases as x increases, what is the sign of the gradient?
Negative
Positive
Undefined
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Negative Falling from left to right is negative gradient.
Check 6
What is the change in y from (1, 2) to (5, 10)?
8
4
2
Show answer
8 10 - 2 = 8.
Check 7
What is the change in y from (2, 6) to (5, 0)?
-6
6
-3
Show answer
-6 0 - 6 = -6.
Check 8
A line has gradient 3 and passes through (0, 1). What is y when x = 2?
7
6
5
Show answer
7 y = 3(2) + 1 = 7.
Check 9
A line has gradient 2 and passes through (0, 4). What is y when x = 3?
10
6
8
Show answer
10 y = 2(3) + 4 = 10.
Check 10
Why is gradient not equal to change in x divided by change in y?
Gradient measures vertical rise per horizontal step
Because x is always bigger
Because y comes first alphabetically
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Gradient measures vertical rise per horizontal step By definition, slope is vertical change divided by horizontal change.
Check 11
In y = mx + c, which letter represents the gradient?
m
c
x
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m m is the multiplier of x (the gradient).
Check 12
What is the gradient of the line through (2, 3) and (5, 12)?
3
9
4
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3 (12 - 3) / (5 - 2) = 9 / 3 = 3.
Check 13
A line has gradient 4 and passes through (0, 1). What is y when x = 2?
9
8
7
Show answer
9 y = 4(2) + 1 = 9.
Check 14
What is the gradient of a horizontal line?
0
1
Undefined
Show answer
0 There is zero vertical change (dy = 0).
Check 15
What is the gradient of the line through (0, 1) and (3, 7)?