Use letters to represent any integer, odd, even or multiple, then expand and factorise to prove a statement is always true. It is Higher only, aimed at grade 8. Free questions with answers are on this page. Worked examples show each line before you try the questions.
Algebraic proof at GCSE is identities and 'show that n is always…'. Even numbers 2k, odd 2k+1, consecutive n,n+1,n+2, consecutive even 2n,2n+2. Expand, collect, and factor to the form the question named ('a multiple of 4', 'always odd'). Every line needs an equals sign that is actually true, not a wish.
Counter-examples disprove a false claim: one number that fails is enough. For 'show that (n+1)2−(n−1)2=4n', expand both squares and subtract — do not start from 4n. Finish with 'which is a multiple of 4' or 'as required'.
To prove a statement for all integers, write even as 2n and odd as 2n+1 (use a second letter if there are two numbers). Expand, collect, and factor out 2 (even) or write 2(…)+1 (odd). A single counter-example kills a 'always' claim.
Objectives
Write a general integer with a letter.
Expand and factor the expression.
Do not test one number and stop.
Key points
Represent numbers algebraically: any integer n, an even number 2n, an odd number 2n+1, consecutive integers n,n+1,n+2.
Use different letters (n and m) for two numbers that are not linked.
Expand brackets, including (2n+1)2, and simplify accurately.
Factorise the result to show it is a multiple of the required number, or write it as 2(…)+1 to show it is odd.
Worked examples
Example 1
The odd numbers 2k+1 and 2k+3 are consecutive odds. Write their sum in a factorised form.
2 marks
(2k+1)+(2k+3)=4k+4
4k+4=4(k+1)
4(k+1)
Answer: 4(k+1)
Common slips
Slip: 1+3=4 Use the letters, not one example pair.
Slip: 4k+4 cannot be factored 4 is a common factor.
Slip: k+1 The 4 has to stay in the answer.
Example 2
Three consecutive integers start at n. Write their sum in factorised form.
2 marks
n+(n+1)+(n+2)
3n+3
3(n+1)
Answer: 3(n+1)
Common slips
Slip: 1+2+3 Keep n in the expression.
Slip: 3n The +1 and +2 still add to 3.
Slip: n+1 Factor out 3.
Example 3
Write (2n+1)^2-(2n-1)^2 as a single term in n.
3 marks
Difference of squares: the gap in the brackets is 2
(2)(4n)=8n
8n
Answer: 8n
Common slips
Slip: Square 1 and 3 only This has to work for every n.
Slip: 4n 4n is only the sum of the two brackets. Multiply it by the gap, 2.
Slip: 8 Keep the letter. The answer is 8 times n, not just 8.
Questions and answers
GCSE Maths proof questions and answers. Try each one, then open the answer. Easy questions come first.
Question 1 Easy2 marks
Add the consecutive odd numbers 2k+1 and 2k+3, then factor the sum.
Show answer
Answer: 4(k+1)
Add to 4k+4.
Take out 4.
M1 — Add to 4k+4.
A1 — Answer 4(k+1)
Question 2 Easy2 marks
Two consecutive integers start at n. Write their sum as a simplified expression.
Show answer
Answer: 2n+1
n+(n+1).
That is 2n+1.
M1 — n+(n+1).
A1 — Answer 2n+1
Question 3 Medium2 marks
Prove the sum of three consecutive integers from n is a multiple of 3, and give the factorised sum.
Show answer
Answer: 3(n+1)
3n+3.
Factor 3.
M1 — 3n+3.
A1 — Answer 3(n+1)
Question 4 Medium2 marks
Simplify (n+1)^2-(n-1)^2.
Show answer
Answer: 4n
Gap of the brackets is 2.
Sum of the brackets is 2n.
M1 — Gap of the brackets is 2.
A1 — Answer 4n
Question 5 Hard2 marks
Show that the difference of the squares of the odd numbers 2n+1 and 2n-1 is a multiple of 8. Give the simplified difference.
Show answer
Answer: 8n
Use the difference of squares.
The product is 8n.
M1 — Use the difference of squares.
A1 — Answer 8n
Question 6 Hard2 marks
The product of two consecutive integers n and n+1 is even. Write that product.
Show answer
Answer: n(n+1)
The two integers are consecutive, so one is even.
The product is n(n+1).
M1 — The two integers are consecutive, so one is even.
A1 — Answer n(n+1)
Question 7 Exam-style4 marks
Prove that the sum of two consecutive odd numbers is a multiple of 4. Give the factorised sum, taking the first odd number as 2k+1.
Show answer
Answer: 4(k+1)
Second odd number is 2k+3.
Sum 4k+4.
4(k+1).
M1 — Second odd number
M1 — Sum
M1 — Factor 4
A1 — 4(k+1)
Common mistakes
Most lost marks on this topic are one slip.
Testing a few numbers and calling it a proof
Use a letter such as n so the argument covers every integer
Writing two consecutive odd numbers as 2n+1 and 2n+1
Consecutive odd numbers are 2k+1 and 2k+3
Stopping at 4k+4
Factor to 4(k+1) and say that k+1 is an integer
Spot the slip
A student shows that 1+3=4 and says the sum of two consecutive odd numbers is always a multiple of 4. What is wrong?
One pair is not a proof
1+3 is not 4
Odd numbers cannot be added
Show the slip
One pair is not a proof A proof has to cover every pair, so use 2k+1 and the next odd number.
Exam tips
Be ready to do this without a calculator. Paper 1 is the non-calculator paper.
If the question says “show that”, the result is given. The marks are for the steps that reach it.
The method is the same on AQA-style and Edexcel-style papers.
Start with a 'Let …' line that defines each letter. It is often the first mark and it stops you mixing letters up.
Show the factorised form with the required factor at the front, then state in words why that proves the result.
Printable worksheet
The same questions are in a PDF you can print. Answers start on a later page.