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Problem-solving with ratio & algebra – GCSE Maths

Foundation and Higher · Grade 6

Jump to the questions and answers · Download the worksheet (PDF)

Solve ratio problems where the ratio changes, two ratios must be combined, or you need to set up an equation. It is on Foundation and Higher, aimed at grade 6. Free questions with answers are on this page. Worked examples show each line before you try the questions.

Higher ratio questions mix algebra with parts. If and , write by making the s match: and , so . If one amount is an expression, the parts become expressions and the story (total, difference, fraction of) becomes an equation.

A ratio of areas or a ratio after a percentage change is still parts, with an extra line first. Define a letter as 'one part' only when every quantity is a multiple of that part; otherwise let be a named amount and write the others in terms of .

Chain two ratios by matching the shared letter (LCM of the two middle numbers). Combined with a total, one part is total sum of parts. means .

Objectives

Key points

Worked examples

Example 1

3 pens and 2 pencils cost £13. A pen costs £1 more than a pencil. Find the cost of a pencil.

2 marks

  1. Let a pencil cost x. Then a pen costs x + 1
  2. Form equation: 3(x + 1) + 2x = 13, so 5x + 3 = 13
  3. Subtract 3: 5x = 10, so x = 2. A pencil costs £2

Answer: 2

Common slips
  • Slip: Assume pens and pencils cost the same Pens cost £1 more, so their price is x + 1.
  • Slip: Tom wrote 13 13 is the total bill, not the pencil price.
  • Slip: Stop at 5x = 10 Divide by 5 to find the cost of one pencil.

Example 2

Share £40 in the ratio 3:5. Find the larger share.

2 marks

  1. Find total ratio parts: 3 + 5 = 8 parts
  2. Value of one part: 40 / 8 = £5
  3. Multiply by 5 for the larger share: 5 × 5 = £25

Answer: 25

Common slips
  • Slip: Divide 40 by 3 You must divide by the total number of parts, not one ratio number.
  • Slip: Uma wrote 15 15 is 3 parts, which is the smaller share.
  • Slip: State the smaller share £15 The question asks for the larger share.

Example 3

Val is twice as old as Wes and together they are 36. Find the younger age.

3 marks

  1. Let Wes (the younger) be x. Then Val is 2x
  2. Form equation: x + 2x = 36, giving 3x = 36
  3. Divide by 3: x = 12. The younger age is 12

Answer: 12

Common slips
  • Slip: Assume they are both 18 One is twice as old, so their ages are in the ratio 1:2.
  • Slip: Val wrote 18 18 splits the age evenly in half instead of 1:2.
  • Slip: State the older age 24 The question specifically asks for the younger age.

Questions and answers

GCSE Maths problem-solving with ratio & algebra questions and answers. Try each one, then open the answer. Easy questions come first.

Question 1 Easy2 marks

4 pens and 4 pencils cost £24. A pen costs £2 more than a pencil. Find the cost of a pencil.

Show answer

Answer: 2

  1. Four pens add 4 × £2 = £8 extra.
  2. Subtract extra: £24 - £8 = £16 for 8 items, so 16 / 8 = 2.
  • M1 — Four pens add 4 × £2 = £8 extra.
  • A1 — Subtract extra: £24 - £8 = £16 for 8 items, so 16 / 8 = 2.

Question 2 Easy2 marks

2 pens and 3 pencils cost £13. A pen costs £2 more than a pencil. Find the cost of a pencil.

Show answer

Answer: 1.80

  1. Two pens add 2 × £2 = £4 extra.
  2. Subtract extra: £13 - £4 = £9 for 5 items, so 9 / 5 = 1.8, which is £1.80.
  • M1 — Two pens add 2 × £2 = £4 extra.
  • A1 — Subtract extra: £13 - £4 = £9 for 5 items, so 9 / 5 = 1.8, which is £1.80.

Question 3 Medium2 marks

Share £48 in the ratio 1:2. Find the larger share.

Show answer

Answer: 32

  1. Total parts: 1 + 2 = 3 parts. One part is 48 / 3 = 16.
  2. Larger share is 2 parts: 2 × 16 = 32.
  • M1 — Total parts: 1 + 2 = 3 parts. One part is 48 / 3 = 16.
  • A1 — Larger share is 2 parts: 2 × 16 = 32.

Question 4 Medium2 marks

Share £36 in the ratio 2:7. Find the larger share.

Show answer

Answer: 28

  1. Total parts: 2 + 7 = 9 parts. One part is 36 / 9 = 4.
  2. Larger share is 7 parts: 7 × 4 = 28.
  • M1 — Total parts: 2 + 7 = 9 parts. One part is 36 / 9 = 4.
  • A1 — Larger share is 7 parts: 7 × 4 = 28.

Question 5 Hard2 marks

Flo is twice as old as Gil and together they are 45. Find the younger age.

Show answer

Answer: 15

  1. Total ratio parts: 1 + 2 = 3 parts.
  2. Divide total: 45 / 3 = 15 for the younger age.
  • M1 — Total ratio parts: 1 + 2 = 3 parts.
  • A1 — Divide total: 45 / 3 = 15 for the younger age.

Question 6 Hard2 marks

Hap is twice as old as Ida and together they are 24. Find the younger age.

Show answer

Answer: 8

  1. Total ratio parts: 1 + 2 = 3 parts.
  2. Divide total: 24 / 3 = 8 for the younger age.
  • M1 — Total ratio parts: 1 + 2 = 3 parts.
  • A1 — Divide total: 24 / 3 = 8 for the younger age.

Question 7 Exam-style4 marks

5 adults and 3 children cost £55 in total. An adult ticket costs £3 more than a child ticket. Work out the cost of an adult ticket.

Show answer

Answer: 8

  1. Let a child ticket cost c. An adult ticket costs c + 3.
  2. Form the equation: 5(c + 3) + 3c = 55.
  3. Expand and collect: 8c + 15 = 55, so 8c = 40 and c = 5.
  4. An adult ticket costs 5 + 3 = £8.
  5. Check: 5 × 8 + 3 × 5 = 40 + 15 = 55.
  • M1 — Adult price written as c + 3
  • M1 — 5(c + 3) + 3c = 55
  • M1 — 8c = 40 or c = 5
  • A1 — Adult ticket £8

Common mistakes

Most lost marks on this topic are one slip.

  1. Giving the whole bill as the price of one pencil

    Remove the extra pounds, then share the rest

  2. Giving the smaller part when the question asks for the larger share

    Use the larger number in the ratio

  3. Halving an age total when one person is twice the other

    Split the total into 3 parts

Spot the slip

3 pens and 2 pencils cost £13. A pen costs £1 more than a pencil. Sue says a pencil is £13. What does a pencil cost?

  1. 2
  2. 13
  3. 3
Show the slip

2 Three extra pounds for the pens leave £10 for five items, so a pencil is £2.

Exam tips

Printable worksheet

The same questions are in a PDF you can print. Answers start on a later page.

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Questions students ask

Is Problem-solving with ratio & algebra Foundation or Higher?

Problem-solving with ratio & algebra is on Foundation and Higher, aimed at grade 6.

What is a common slip on Problem-solving with ratio & algebra?

Giving the whole bill as the price of one pencil. Remove the extra pounds, then share the rest.

Where can I get Problem-solving with ratio & algebra questions and answers?

The questions on this page are free. Open Show answer under each one, or download the worksheet PDF. Start free to practise this topic in the app.

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Last updated 9 November 2026.

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