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3D Pythagoras & trigonometry – GCSE Maths

Higher · Grade 7 · Calculator

Jump to the questions and answers · Download the worksheet (PDF)

Find lengths and angles inside cuboids and pyramids by pulling out the right 2D right-angled triangle. It is Higher only, aimed at grade 7. Free questions with answers are on this page. Worked examples show each line before you try the questions.

3D Pythagoras and trig are 2D in disguise. Draw the right-angled triangle that actually contains the length or angle you want. A cuboid's space diagonal is (face diagonal first, then a second Pythagoras). An angle between a line and the plane is the angle between the line and its shadow on the plane.

SOHCAHTOA on that slice: the height of a pyramid, the diagonal of a room, the angle a space diagonal makes with the floor. Never apply a trig ratio to a 3D sketch without a right-angled 2D triangle drawn and labelled. Keep unrounded lengths for a follow-up angle.

Space diagonal of a cuboid . Often two steps: face diagonal, then space diagonal. An angle with the base: .

Objectives

Key points

Worked examples

Example 1

Find the face diagonal of the 3 by 4 face.

2 marks

  1. State Pythagoras for the rectangular face: d² = 3² + 4².
  2. Calculate sum of squares: d² = 9 + 16 = 25.
  3. Take square root: d = √25 = 5.

Answer: 5

Common slips
  • Slip: Add edge lengths directly: 3 + 4 = 7. Diagonal requires sum of squares, not sum of lengths.
  • Slip: Multiply dimensions: 3 × 4 = 12. 3² = 9 and 4² = 16.
  • Slip: Leave d² = 25 without square rooting. The diagonal length is √25 = 5.

Example 2

Find the space diagonal of a cuboid 3 by 4 by 12.

2 marks

  1. Apply 3D Pythagoras formula: d² = a² + b² + c² = 3² + 4² + 12².
  2. Calculate squares: d² = 9 + 16 + 144 = 169.
  3. Take square root: d = √169 = 13.

Answer: 13

Common slips
  • Slip: Use 2D Pythagoras on two edges: 3² + 4². 3D space diagonal requires all three edge lengths.
  • Slip: Calculate d² = 25 + 12 = 37. The third edge 12 must be squared: 12² = 144.
  • Slip: Write d = 5. √169 = 13.

Example 3

A cuboid has base 3 by 4 and height 12. Find the tan of the angle between the diagonal and the base.

3 marks

  1. Find base diagonal: √(3² + 4²) = √25 = 5.
  2. Identify opposite side (height = 12) and adjacent side (base diagonal = 5).
  3. Calculate tan θ = opposite / adjacent = 12/5.

Answer: 12/5

Common slips
  • Slip: Use single edge 3 or 4 as base. The triangle inside the cuboid uses the base diagonal.
  • Slip: Identify space diagonal 13 as adjacent side. The space diagonal is the hypotenuse of the triangle.
  • Slip: Write sin θ = 12/13. tan θ = opposite / adjacent = 12/5.

Questions and answers

GCSE Maths 3d pythagoras & trigonometry questions and answers. Try each one, then open the answer. Easy questions come first.

Question 1 Easy2 marks

Find the face diagonal of the 6 by 8 face.

Show answer

Answer: 10

  1. 6² + 8² = 100.
  2. The face diagonal is 10.
  • M1 — 6² + 8² = 100.
  • A1 — Answer 10

Question 2 Easy2 marks

Find the space diagonal of a cuboid 2 by 3 by 6.

Show answer

Answer: 7

  1. 2² + 3² + 6² = 49.
  2. The space diagonal is 7.
  • M1 — 2² + 3² + 6² = 49.
  • A1 — Answer 7

Question 3 Medium2 marks

The space diagonal is 13 and the base is 3 by 4. Find the height.

Show answer

Answer: 12

  1. 3² + 4² = 25.
  2. 13² − 25 = 144, so the height is 12.
  • M1 — 3² + 4² = 25.
  • A1 — Answer 12

Question 4 Medium2 marks

A cuboid is 3 by 4 by 12. Find the angle between the space diagonal and the base to the nearest degree.

Show answer

Answer: 67

  1. The base diagonal is 5.
  2. tan of the angle is 12/5, so the angle is 67 degrees.
  • M1 — The base diagonal is 5.
  • A1 — Answer 67

Question 5 Hard2 marks

Find the face diagonal of the 5 by 12 face.

Show answer

Answer: 13

  1. 5² + 12² = 169.
  2. The face diagonal is 13.
  • M1 — 5² + 12² = 169.
  • A1 — Answer 13

Question 6 Hard2 marks

Find the space diagonal of a cuboid 1 by 4 by 8.

Show answer

Answer: 9

  1. 1 + 16 + 64 = 81.
  2. The space diagonal is 9.
  • M1 — 1 + 16 + 64 = 81.
  • A1 — Answer 9

Question 7 Exam-style4 marks

The base diagonal is 12 and the angle with the base is 45 degrees. Find the height to 3 significant figures.

Show answer

Answer: 12.0

  1. tan 45 = 1, so the height equals the base diagonal.
  2. The height is 12.0 to 3 significant figures.
  • M1 — tan 45 = 1, so the height equals the base diagonal.
  • M1 — The height is 12.0 to 3 significant figures.
  • A1 — The height is 12.0 to 3 significant figures.
  • B1 — Answer 12.0

Common mistakes

Most lost marks on this topic are one slip.

  1. Stopping at the face diagonal

    The space diagonal passes through the 3D interior and must include all three dimensions

  2. Using the space diagonal in tan

    tan θ = opposite / adjacent uses the base diagonal, not the space diagonal

  3. Leaving the fraction unsimplified

    Always cancel fractions to simplest form (e.g. 24/10 = 12/5)

Spot the slip

A cuboid is 3 by 4 by 12. The base diagonal is 5. A student uses that 5 as the space diagonal. What is the space diagonal?

  1. 13
  2. 5
  3. 12
Show the slip

13 Space diagonal = √(3² + 4² + 12²) = √(9 + 16 + 144) = √169 = 13.

Exam tips

Printable worksheet

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Questions students ask

Is 3D Pythagoras & trigonometry Foundation or Higher?

3D Pythagoras & trigonometry is Higher only, aimed at grade 7.

What is a common slip on 3D Pythagoras & trigonometry?

Stopping at the face diagonal. The space diagonal passes through the 3D interior and must include all three dimensions.

Where can I get 3D Pythagoras & trigonometry questions and answers?

The questions on this page are free. Open Show answer under each one, or download the worksheet PDF. Start free to practise this topic in the app.

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Last updated 9 November 2026.

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